How many moles of NaCl are produced from 16.5g of HCl, according to the neutralization reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(I)
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Answer:
How many moles of NaCl are produced from 16.5g of HCl, according to the neutralization reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(I) 0.452.